Yes, but if anyone does any more, you can assert that

but only if you show that

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- Jun 9th 2008, 11:48 AMMathstud28
- Jun 9th 2008, 12:35 PMMathstud28
Ok, here is a really really easy one.

where

EDIT: oops...a typo - Jun 9th 2008, 01:28 PMwingless
- Jun 9th 2008, 01:33 PMMathstud28
No takers? Oh well,

There are a couple of ways to do this.

The smart*** way would be that since

we have that

This can be shown by the limit

this was gotten from the fact that if

Therefore

The other answer that is better in my opinion would be the use of the ratio/root test trick

Now by termwise division with

we get

- Jun 9th 2008, 01:35 PMMathstud28
Good answer! The only thing is, that you did not show that all the other terms can be ignored via a limit as I did in mine (No big deal, I think we all know it to be true)...and did you just use L'hopital's?:D

If anyone sees a problem with any of my solutions let me know - Jun 9th 2008, 01:45 PMwingless
Well, my first answer is the same as yours, I just didn't show the details. And if you don't want to evaluate the limit using , use the L'hopital solution.. =)

- Jun 9th 2008, 02:04 PMMathstud28
EDIT:(sorry, I am making these up as we go) Tis is another easy one, if someone would like to post another one I would be more than happy to give up the posting position

Find the smallest integer such that

- Jun 9th 2008, 04:03 PMMathstud28
- Jun 9th 2008, 04:13 PMtopsquark
- Jun 9th 2008, 04:43 PMMathstud28
- Jun 9th 2008, 04:49 PMtopsquark
- Jun 9th 2008, 04:52 PMMathstud28
- Jun 9th 2008, 05:16 PMgalactus
Try these:

- Jun 9th 2008, 05:26 PMMathstud28
- Jun 9th 2008, 05:34 PMtopsquark