Problem:Find the equation of the plane containing the point $\displaystyle A(5, -3, 6)$ that is parallel to the lines $\displaystyle \frac {x-3}{1}$ = $\displaystyle \frac {y-3}{2}$ = $\displaystyle \frac {z+2}{-3}$ and $\displaystyle \frac {x-8}{2}$ = $\displaystyle \frac {y-9}{1}$, $\displaystyle Z=2$.

Answer: $\displaystyle x-2y-z-5=0$

Comments:I haven't studied matrices, so including them will just confuse me further. This question is practice for my final exam. Please help me!