# Thread: Equation of a Plane Problem Help

1. ## Equation of a Plane Problem Help

Problem:

Find the equation of the plane containing the point $A(5, -3, 6)$ that is parallel to the lines $\frac {x-3}{1}$ = $\frac {y-3}{2}$ = $\frac {z+2}{-3}$ and $\frac {x-8}{2}$ = $\frac {y-9}{1}$, $Z=2$.

Answer: $x-2y-z-5=0$

2. Find the cross product $\left\langle {1,2, - 3} \right\rangle \times \left\langle {2,1,0} \right\rangle$. That is the cross product of the two directions vectors of the given lines.