y=(tan^2(x))
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Originally Posted by Bryn y=(tan^2(x)) Note that $\displaystyle \tan^2(x)=\sec^2(x)-1$ Thus, $\displaystyle \int\tan^2(x)\,dx=\int\left[\sec^2(x)-1\right]\,dx=\color{red}\boxed{\tan(x)-x+C}$ Hope this makes sense!
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