isoclines,,,never been very good with limits
can u cancel infinty,,,,this is probably a very stupid/petty question!!Q is find the equation of the straight line on which the gradient of the solution curve is infinite. I made the presumption that this straight line would essentially be an isocline(hopefulli im ryt) and did the follwing,, Is is more accurate using the D.e and making bottom=0???Or is my working ok?!
putting constant as infinity and rearranging to f(x)
(i) y= -x(1-m)/(m-3)
(ii) y= -x(1-inf)/(inf-3) implies(i think) y= -x(inf)/(inf)
y = -x
is this okai???