I have to find y'' for rad(t^3+1) I got y' = 3t^2/(2rad(t^3+1) i need help with y'' I cannot get to the answer
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You calculated y' correctly. To calculate y'', you can use the quotient rule: In case you forgot:
Originally Posted by weezie23 I have to find y'' for rad(t^3+1) I got y' = 3t^2/(2rad(t^3+1) i need help with y'' I cannot get to the answer rad? If you mean Then let Differentiating we get Or Remembering our original equation is y we get So now we take the second derivative first rewriting this as So I think you can go from there
I included the 2/3 while calculating q. rule. Thanks!
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