u= w^3 du= 3w^2dw integral 1/3[u (u-1)^1/2 du 1/3 [ u^3/2 -udu] 1/3 [[ 2/5(u^5/2) - 1/2u^2]] the answer is 1/3[2/5(u^5/2) - 2/3(u^3/2) what did I do wrong in the second part?
Follow Math Help Forum on Facebook and Google+
Make your subs: Seems like you messed up dealing with w^5.
Substitution will kill quickly the problem.
View Tag Cloud