how would one solve this? I used integration by parts and got (3+2x^2)lnx - 1/2x^2lnx - 1/4x^2 it's a differential equation os 1/3y^3 = (3+2x^2)lnx - 1/2x^2lnx - 1/4x^2 where y(1) = 0
Follow Math Help Forum on Facebook and Google+
Originally Posted by khuezy how would one solve this? I used integration by parts and got (3+2x^2)lnx - 1/2x^2lnx - 1/4x^2 it's a differential equation os 1/3y^3 = (3+2x^2)lnx - 1/2x^2lnx - 1/4x^2 where y(1) = 0 By parts is not required, you can do it this way...
Originally Posted by Isomorphism By parts is not required, you can do it this way... *Ahem*
View Tag Cloud