How did people get the integral of 1 to be 3/2(x)? I'm confused. what is the integral of sin^2(x)?
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Do you mean: First off, As for integrating , use the double angle identity:
I got 1/2x -1/4sin(2x) how do I put this back in terms of sin(t) = x-1 (the original problem is integral of (x^2)/(squareroot of (1-(x-1)^2)
Originally Posted by khuezy I got 1/2x -1/4sin(2x) how do I put this back in terms of sin(t) = x-1 (the original problem is integral of (x^2)/(squareroot of (1-(x-1)^2) You made the substitution , yes? So, we have: , , and Now just make the appropriate substitutions.
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