does any body know how to write an iteration to compute y in y-log(y)=x ?
(I assume your question is on Newton's Method cuz that is what you asked the other time).
You want to solve,
Which is equivalent to,
The iteration sequence is,
And yet one more time, (watch those signs )
Finally we have,
With , then should be OK. But then experimenting with theOriginally Posted by dan
iteration as given by PH it appears to diverge with , or !
It must be a mistake in PH's algebra as the iteration (which is what PH had before he tried simplifying it):
does converge with , to after two iterations.
I don't know whether it is an iteration formula or not.Originally Posted by dan
You are given x
Guess any value of a(a is iterating variable, should be greater than x)
You will get some value
this is your next value of a
Substitute it again in the above expression.
After some steps it will give the answer(when you the same value of a for two times)
Note: I am not sure about this idea, please someone check it.