Let R be the region bounded by the curves y=x^2, y=sin(xpi/2), x=0, and x=1.
Find the volume of the solid obtained by rotating R around the y-axis.
Follow Math Help Forum on Facebook and Google+
A graph of this would be helpful in visualizing what's going on.
By method of shells:
x = the radius of the shell; = represents the height of te shell
how would i solve that integral? it looks complicated
It's not too bad:
You can integrate term by term (since: ) in which case the 2nd term should be rather easy.
The first one, i.e. requires integration by parts:
Sub it into the integration by parts formula and you should be on your way.
View Tag Cloud