Given that x = 4sin(2y+6), find (dy/dx) in terms of x.

i have managed to get:

(dy/dx) = 1/8cos(2y+6)

where do i go from here?

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- Jun 5th 2008, 06:45 AMStylis10Trigonometric Differentiation
Given that x = 4sin(2y+6), find (dy/dx) in terms of x.

i have managed to get:

(dy/dx) = 1/8cos(2y+6)

where do i go from here? - Jun 5th 2008, 07:18 AMIsomorphism
- Jun 5th 2008, 07:44 AMStylis10
- Jun 5th 2008, 07:48 AMStylis10
ok i understand how you got that, thanxs

- Jun 5th 2008, 07:50 AMSoroban
Hello, Stylis10!

Quote:

Given: . , .find in terms of

i have managed to get: . . . . . Good!

where do i go from here?

We are given: .

So is an angle in a right triangle with: .

. . From Pythagorus, we have: .

Hence: .

Substitute into your equation: .

Therefore: .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

For the fun of it, I did it another way.

. . (I've got to get a life!)

We have: .

. . .

Then: .

. . . . .

Therefore: . ta-*DAA!*