Find a Maclaurin series expansion for each function.
f(x) = cos x
f(x) = 1/(1-x)
f(x) = x sin x
These are pretty standard but if the intent is to "discover" these on your own, just directly apply the formula for the Maclaurin series (a taylor series centred around a = 0):
Taking a = 0:
For the f(x) = cos x, you would need to find:
, , ..
Then generalize a pattern and that should be your Maclaurin series (Of course, if you wanted to prove it you can do it with induction to verify your series).
Also, a google search for maclaurin series would probably give you these results.
this is applicable
Because applying the use of the root test for finding intervals of convergence we get
Therefore we run into an identity verifying that cos(x) is analytic across the reals
Either recognize this as the converse of the sum of an infinite geometric seires or notice that the temrs are given by
Using the Root test again we get
Now seeing that at x=1 and x=-1 we have a divergent series this function is analytic only on
For the third I will leave it up to you to show the termiwise derivation but
and applying the ratio or root test again we see this is also analytic across the reals