Thread: Derivative of reciprocal functions

Hi, I have a question asking: "f(x) is a differentiable function. Find the derivative of the recip. function g(x) = 1/f(x) at those points where f(x) does not = 0."

What exactly am I finding the derivative of here? g'(x) = -1/f(x)^2?

Originally Posted by SportfreundeKeaneKent

Hi, I have a question asking: "f(x) is a differentiable function. Find the derivative of the recip. function g(x) = 1/f(x) at those points where f(x) does not = 0."

What exactly am I finding the derivative of here? g'(x) = -1/f(x)^2?

use the chain rule: ...you'd get the same thing using the quotient rule

Due to the numerator being the derivative of f(x), f(x) must be differentiable, which is why it mentions it in the problem. It can throw some people off. But it's necessary information.

Originally Posted by Aryth

Due to the numerator being the derivative of f(x), f(x) must be differentiable, which is why it mentions it in the problem. It can throw some people off. But it's necessary information.

indeed. and of course g(x) is undefined if f(x) is 0, which is why we are also told this is not the case