# Math Help - Check answer for this difinate integral

1. ## Check answer for this difinate integral

Hi,

I keep coming up with an answer of 32/225. However the answer sheet has it as 16/225.

The question is evaluate the integral of 4/(1+2t)^3 on the interval of [1,2]

2. Originally Posted by Craka
Hi,

$\int_1^{2}\frac{4}{(1+2t)}dt=2\int_1^{2}\frac{2}{( 1+2t)^3}=2\bigg[\frac{-1}{2(1+2t)^2}\bigg]\bigg|_1^{2}=\frac{16}{225}$