Originally Posted by

**Kim Nu** Hey thanks Empty Set,

Now my posts are definitely getting annoying but:

I took your suggestion, which is the correct course of action; I end up with

x2 = c3cos(t) + c4sin(t) + c3e^(-2t) + 2e^(-t)

Then I take the before mentioned solved x1 value and x2 value and plug them into E2: Dx1 - (D + 2)x2 = -3e^(-t)

I work this all out and end up with:

sin (t)[-c1 + c3 -2c4] + cos (t)[c2 - c4 - 2c3) = -8e^(-t)

The answer in the back of the book is:

x1 = 5c1cost(t) + 5c2sin(t) + e^(-t)

x2 = (c1 + 2c2)cost + (-2c1 + c2)sin(t) + c3e^(-2t) + 2e^(-t)

So my answers are close to being correct, I just don't understand how those coefficient were arrived at. Do you have any suggestions? Thanks,

Kim