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Math Help - Extreme Value Problems

  1. #1
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    Extreme Value Problems

    A box with an open top is to be constructed from a square piece of cardboard, 6 meters wide, by cutting out a square from each of the four corners, and bending up the sides. Find the largest volume that such a box can have.



    Let x represent the dimensions

    V = (6 - 2x)^2x
    V = 36x - 24x^2 + 4x^{3}

    V' = 36 - 48x + 12x^2
    0 = 36 - 48x + 12x^2
    0 = 12(x - 1)(x - 3)

    x = 1 and x = 3


    Restrictions:  0 \leq x \leq 3

    V = Lwh
    V = (3)(1)(6)
    V = 18m^{3}

    ---------

    Text Answer is 16m^{3}

    Please help me correct my work?
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  2. #2
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    Quote Originally Posted by Macleef View Post
    A box with an open top is to be constructed from a square piece of cardboard, 6 meters wide, by cutting out a square from each of the four corners, and bending up the sides. Find the largest volume that such a box can have.



    Let x represent the dimensions

    V = (6 - 2x)^2x
    V = 36x - 24x^2 + 4x^{3}

    V' = 36 - 48x + 12x^2
    0 = 36 - 48x + 12x^2
    0 = 12(x - 1)(x - 3)

    x = 1 and x = 3


    Restrictions:  0 \leq x \leq 3

    V = Lwh
    V = (3)(1)(6)
    V = 18m^{3}

    ---------

    Text Answer is 16m^{3}

    Please help me correct my work?
    You need to plug into the volume formula

    V(x) = (6 - 2x)^2x

    V(1) = (6 - 2(1))^2(1)=(4)^2=16
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