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  1. #1
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    calc 1 question

    question is f(3) =2, f'(3)=4 g(3)=8 g'(3)=3 Find h'(3)=fx/gx

    does this relate to dy/dx=dy/du*du/dx....?
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  2. #2
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    Quote Originally Posted by weezie23 View Post
    question is f(3) =2, f'(3)=4 g(3)=8 g'(3)=3 Find h'(3)=fx/gx

    does this relate to dy/dx=dy/du*du/dx....?
    If I'm reading your problem correctly that is exactly it. So h'(3) = 4/3.

    -Dan
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  3. #3
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    Hello, weezie23!

    I'm guessing that you left out part of the problem.


    f(3) \:=\:2,\quad f'(3)\:=\:4,\quad g(3)\:=\:8,\quad  g'(3)\:=\:3,\quad h(x) \:=\:\frac{f(x)}{g(x)}

    Find h'(3)
    We have: . h(x) \:=\:\frac{f(x)}{g(x)}

    . . Quotient Rule: . h'(x) \;=\;\frac{g(x)f'(x) - f(x)g'(x)}{[g(x)]^2}


    Since h'(3) \;=\;\frac{g(3)f'(3) - f(3)g'(3)}{[g(3)]^2}

    . . we have: . h'(3) \;=\;\frac{8\!\cdot\!4 - 2\!\cdot\!3}{8^2} \;=\;\frac{26}{64}\;=\;\frac{13}{32}

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