question is f(3) =2, f'(3)=4 g(3)=8 g'(3)=3 Find h'(3)=fx/gx does this relate to dy/dx=dy/du*du/dx....?
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Originally Posted by weezie23 question is f(3) =2, f'(3)=4 g(3)=8 g'(3)=3 Find h'(3)=fx/gx does this relate to dy/dx=dy/du*du/dx....? If I'm reading your problem correctly that is exactly it. So h'(3) = 4/3. -Dan
Hello, weezie23! I'm guessing that you left out part of the problem. Find We have: . . . Quotient Rule: . Since . . we have: .
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