Well, there will be several ones. It were really helpful if someone could also explain some details;

1) I (x^3-x^2-3x+1)/(x^2+x-2)dx

2) I sin4x*sin5x dx

3) I e^cosx sinx dx

4) I x artctgx dx

5) I (1/x^2)*e^1/x dx

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- June 2nd 2008, 03:08 AMlightbirdHelp on indefinite integration needed!
Well, there will be several ones. It were really helpful if someone could also explain some details;

1) I (x^3-x^2-3x+1)/(x^2+x-2)dx

2) I sin4x*sin5x dx

3) I e^cosx sinx dx

4) I x artctgx dx

5) I (1/x^2)*e^1/x dx

- June 2nd 2008, 04:00 AMSoroban
Hello, lightbird!

Here are a few of them . . .

Quote:

Quote:

Let

Substitute: .

Quote:

Let

Substitute: .

- June 2nd 2008, 04:06 AMmr fantastic
1) Divide the quadratic into the cubic and apply partial fraction decomposition to the remainder to get . Now integrate term-by-term.

2) Apply the identity . In your case A = 4x and B = 5x.

3) Make the substitution .

4) Integration by parts.

5) Make the substitution .