1. ## [SOLVED] Displacement Confusion

"A small object is dragged across a corrugated surface so that its height h above the ground in terms of its horizontal displacement x is given by

h = 2 + (3/2)sin (2x)

The object moves in such a way that the horizontal component of its velocity has a constant value of c, x = 0 at time t = 0.

Find a formula for x in terms of t."

I'm confused as to how I am supposed to obtain x and remove h. I don't understand how the horizontal component relates to this displacement.

2. Originally Posted by Evales
"A small object is dragged across a corrugated surface so that its height h above the ground in terms of its horizontal displacement x is given by

h = 2 + (3/2)sin (2x)

The object moves in such a way that the horizontal component of its velocity has a constant value of c, x = 0 at time t = 0.

Find a formula for x in terms of t."

I'm confused as to how I am supposed to obtain x and remove h. I don't understand how the horizontal component relates to this displacement.
x = ct.

Then, moving along to what I imagine the next part will require,

h = 2 + (3/2)sin (2ct)

3. The next part of the question asks about finding the vertical component of the velocity in relation to t.

4. Originally Posted by Evales
The next part of the question asks about finding the vertical component of the velocity in relation to t.
Get dh/dt.

5. Okay so far I have found why x = ct and now I'm trying to find dh/dt

The only problem is that I can only find x in relation to t AND c.

Because I know c is a constant is it okay to just use that anyway?

dh/dt = dx/dt * dh/dx

6. Originally Posted by Evales
Okay so far I have found why x = ct and now I'm trying to find dh/dt

The only problem is that I can only find x in relation to t AND c.

Because I know c is a constant is it okay to just use that anyway?

dh/dt = dx/dt * dh/dx
Yes.