Hi all,

I am stuck with this question:

Using coshx and sinhx to verify the identity:

(coshx + sinhx)^n = cosh(nx) + sinh(nx)

I have tried using coshx = (e^x + e^(-x))/2 and sinhx = (e^x - e^(-x))/2... and i plugged it in and got (e^x)^n but lol how can i get cosh(nx) + sinh(nx)?

Thanks in advance,

ArTiCK