Originally Posted by

**badi6** Hello everybody,

can anyone help me plz with this problem?

a river, runnung between parallel banks, is 20 m wide. the depth, y metres, of the river measured at point x metres from one bank is given by formula

y = 1/10 * x *√(20-x), 0≤ x ≤20.

the table below, giving values of y to 3 decimal places.

x: 0 4 8 12 16 20

y: 0 1.600 2.771 2.262 3.200 0

by using the trapezium rule with all the values in the table to estimate the cross-area of the river we found A = 39.332

given that the cross-sectional area is constant and that the river is flowing uniformly at 2 m s-1

**Q: **__estimate, in m____3____, the volume__ of water flowing __per minute__, giving your answer to __3 significant figures__.

**Thanks**