# Math Help - Can you check my work?

1. ## Can you check my work?

I was to find the limit as n approaches infinity of [((1+2+3+...+n)/n+2) - n/2].

I changed the numerator to n(n+1)/2 found a common denominator with the second fraction and cleaned it up.

Then, limit as n approaches infinity of -n/(2n+4)

My answer is -1/2

2. Hello, Nichelle14!

Find: $\lim_{n\to\infty}\left[\frac{1 + 2 + 3 + \cdots + n}{n+2} - \frac{n}{2}\right]$

I changed the numerator to $\frac{n(n+1)}{2}$,
found a common denominator with the second fraction and cleaned it up.

Then: . $\lim_{n\to\infty}\left[\frac{-n}{2(n+2)}\right] \;= \;-\frac{1}{2}$
Looks great to me!