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Math Help - Can you check my work?

  1. #1
    Junior Member
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    Can you check my work?

    I was to find the limit as n approaches infinity of [((1+2+3+...+n)/n+2) - n/2].

    I changed the numerator to n(n+1)/2 found a common denominator with the second fraction and cleaned it up.

    Then, limit as n approaches infinity of -n/(2n+4)

    My answer is -1/2
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  2. #2
    Super Member

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    Lexington, MA (USA)
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    Hello, Nichelle14!

    Find: \lim_{n\to\infty}\left[\frac{1 + 2 + 3 + \cdots + n}{n+2} - \frac{n}{2}\right]

    I changed the numerator to \frac{n(n+1)}{2},
    found a common denominator with the second fraction and cleaned it up.

    Then: . \lim_{n\to\infty}\left[\frac{-n}{2(n+2)}\right] \;= \;-\frac{1}{2}
    Looks great to me!
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