Thread: find integral of this

integral( 1/sqrt(x),x, 0,1) = 2sqrt(x)

Originally Posted by szpengchao

integral( 1/sqrt(x),x, 0,1) = 2sqrt(x)

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Now use the exponent rule.

how to?

Originally Posted by szpengchao

how to?

Power Rule:



Does that help?

i mean from definition.... is it the only way to find integral?

Originally Posted by szpengchao

i mean from definition.... is it the only way to find integral?

Mmmm... remember the derivative of ?

It's , recognize it in the integral

i do it by riemann integrable.

define LRS and URS, i suceed to show LRS=URS, but cant show that LRS=2sqrt(a)

m...so we can say, becoz derivative of sqrt(x) is that, so the definite integral =2sqrt(x)

You cannot use the Riemann integral over here. The function is even defined on . If you had then it is possible to do it by definition, but not the way you posted the problem.