integral( 1/sqrt(x),x, 0,1) = 2sqrt(x)
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Originally Posted by szpengchao integral( 1/sqrt(x),x, 0,1) = 2sqrt(x) . Now use the exponent rule.
how to?
Originally Posted by szpengchao how to? Power Rule: Does that help?
i mean from definition.... is it the only way to find integral?
Originally Posted by szpengchao i mean from definition.... is it the only way to find integral? Mmmm... remember the derivative of ? It's , recognize it in the integral
i do it by riemann integrable. define LRS and URS, i suceed to show LRS=URS, but cant show that LRS=2sqrt(a) m...so we can say, becoz derivative of sqrt(x) is that, so the definite integral =2sqrt(x)
You cannot use the Riemann integral over here. The function is even defined on . If you had then it is possible to do it by definition, but not the way you posted the problem.
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