y" + y' = 3x^2 Here's the work I've done: yc: 1. r^2 + r = 0 2. r(r + 1) = 0 3. r=0, -1 4. Thus, yc= c1 +c2e^-x How do I solve for yp? Thanks, JN
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Originally Posted by Jim Newt y" + y' = 3x^2 Here's the work I've done: yc: 1. r^2 + r = 0 2. r(r + 1) = 0 3. r=0, -1 4. Thus, yc= c1 +c2e^-x How do I solve for yp? Thanks, JN To solve for , we assume it takes on the form of a second degree polynomial : Now plug into the DE and solve for the unknown coefficients: Therefore, we have: Comparing the coefficients, we have: This implies that both A and B equal . Therefore, .
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