y" + y' = 3x^2

Here's the work I've done:

yc:

1. r^2 + r = 0

2. r(r + 1) = 0

3. r=0, -1

4. Thus, yc= c1 +c2e^-x

How do I solve for yp? Thanks,

JN

Printable View

- May 27th 2008, 11:42 AMJim NewtAnother Undetermined Coefficient question
y" + y' = 3x^2

Here's the work I've done:

yc:

1. r^2 + r = 0

2. r(r + 1) = 0

3. r=0, -1

4. Thus, yc= c1 +c2e^-x

How do I solve for yp? Thanks,

JN - May 27th 2008, 12:11 PMChris L T521