y" + y' = 3x^2
Here's the work I've done:
yc:
1. r^2 + r = 0
2. r(r + 1) = 0
3. r=0, -1
4. Thus, yc= c1 +c2e^-x
How do I solve for yp? Thanks,
JN
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y" + y' = 3x^2
Here's the work I've done:
yc:
1. r^2 + r = 0
2. r(r + 1) = 0
3. r=0, -1
4. Thus, yc= c1 +c2e^-x
How do I solve for yp? Thanks,
JN