Math Help - Half Width Half Maximum

1. Half Width Half Maximum

Can someone please show me how to find the HWHM of (3/4)(1-X^2), x between -1 and 1. This is a side exercise for my class and I'm a little lost.

Thanks

2. Originally Posted by taypez
Can someone please show me how to find the HWHM of (3/4)(1-X^2), x between -1 and 1. This is a side exercise for my class and I'm a little lost.

Thanks
Do this in steps:

1. What is the maximum value of the function?

2. What is half of that value? (Call it $y_{1/2}$.)

3. Solve $\frac{3}{4}(1 - x^2) = y_{1/2}$ for x.

4. Your answer is the difference between the two solutions of #3.

-Dan