Use polar coordinates to find the volume of the given solid.

Inside the sphere x^2+y^2+z^2=16 and outside the cylinder x^2+y^2=4

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- May 24th 2008, 04:48 PMYanDouble integral in polar coordinates 2
Use polar coordinates to find the volume of the given solid.

Inside the sphere x^2+y^2+z^2=16 and outside the cylinder x^2+y^2=4 - May 24th 2008, 06:07 PMgalactus
On thing you could do is find the volume of the sphere and then the volume of the cylinder, then subtract them. That will be the volume between the sphere and the cylinder.

$\displaystyle V_{s}=\int_{0}^{2\pi}\int_{0}^{\sqrt{16-r^{2}}}\int_{0}^{4}\int_{0}^{2\pi}rdzdrd{\theta}$

This can be checked by just using the formula for the volume of a sphere of radius 4.

$\displaystyle r^{2}=4, \;\ z^{2}=\sqrt{16-r^{2}}$

$\displaystyle z=\pm\sqrt{12}$

The cylinder has height $\displaystyle \sqrt{12}$ and radius 2

It's volume is $\displaystyle V_{c}=\int_{0}^{2\pi}\int_{0}^{2}\int_{0}^{\sqrt{1 2}}rdzdrd{\theta}$

This can be checked by using the formula for the volume of a cylinder with height $\displaystyle \sqrt{12}$ and radius 2.