Results 1 to 2 of 2

Math Help - Double integral in polar coordinates

  1. #1
    Yan
    Yan is offline
    Member
    Joined
    May 2008
    Posts
    103

    Double integral in polar coordinates

    Use polar coordinate to find the volume of the given solid.

    Bounded by the paraboloid z=10-3x^2-3y^2 and the plane z=4.

    I don't know how to defined the r going from where to where and what should be the equation for the double integral.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Eater of Worlds
    galactus's Avatar
    Joined
    Jul 2006
    From
    Chaneysville, PA
    Posts
    3,001
    Thanks
    1
    You can convert 10-3(x^{2}+y^{2})=10-3r^{2}

    10-3r^{2}=4

    r=\pm\sqrt{2}

    Don't forget about the extra r in polar. That gives us 10r-3r^{3}.

    \int_{0}^{2\pi}\int_{0}^{\sqrt{2}}(10r-3r^{3})drd{\theta}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Double Integral with Polar Coordinates
    Posted in the Calculus Forum
    Replies: 1
    Last Post: May 8th 2011, 07:43 AM
  2. Double integral with polar coordinates
    Posted in the Calculus Forum
    Replies: 3
    Last Post: April 20th 2011, 02:44 PM
  3. Double integral in polar coordinates
    Posted in the Calculus Forum
    Replies: 3
    Last Post: January 16th 2010, 07:24 AM
  4. Double integral and polar coordinates
    Posted in the Calculus Forum
    Replies: 2
    Last Post: May 27th 2008, 07:07 PM
  5. Double integral in polar coordinates 2
    Posted in the Calculus Forum
    Replies: 1
    Last Post: May 24th 2008, 06:07 PM

Search Tags


/mathhelpforum @mathhelpforum