The above should be:Originally Posted by freswood
Also it is easier to minimise
RonL
I keep trying this question over and over again, and keep getting the wrong answer. I was wondering if somebody would be nice enough to check my calculations, and see where I went wrong (or if I’m going about it the wrong way!)
Find the minimum distance from the parabola y=x^2 to the point (5,0).
D = √[(x2-x1)^2 + (y2-y1)^2]
I substituted in points (5,0) and (x, x^2)
D = √[(x-5)^2 + x^2
D = √2x^2 - 10x + 25
d/dx = (4x-10)/ [blahblah not important]
0 = 4x-10
4x=10
x=10/4
Substituting this into the D formula doesn't give the right answer ... the answr is apparently 4.06
Thanks!
Hi, freswood,Originally Posted by freswood
I can only think of 2 ways:
1. Use an iteration (for instance Newtons Method)
2. Use Cardanos Formula to solve a reduced cubic equation.
Never mind which method you use, there is only one real solution:
Best wishes
EB