Sigh...calculus is giving me a hard time...Trig was much easier. Anyone recommend a good calculus book to help me put things in perspective? Anyways, I need help with differentiating the following log functions:

1.

2.

thanks

Printable View

- July 1st 2006, 07:34 PMc_323_hDifferentiation of Log functions
Sigh...calculus is giving me a hard time...Trig was much easier. Anyone recommend a good calculus book to help me put things in perspective? Anyways, I need help with differentiating the following log functions:

1.

2.

thanks - July 1st 2006, 07:46 PMThePerfectHackerQuote:

Originally Posted by**c_323_h**

Thus,

Thus,

Thus,

- July 1st 2006, 07:50 PMThePerfectHackerQuote:

Originally Posted by**c_323_h**

Prentice Hall and McGraw-Hill search their sites.

(The books are very expensive).

So you might be tempted to buy,

Calculus for Dummies or Schaum's Outline- I think these publishers are horrific and stay away from them. - July 1st 2006, 10:33 PMc_323_hQuote:

Originally Posted by**ThePerfectHacker**

- July 1st 2006, 11:12 PMSoroban
Hello, c_323_h!

I tried something on #2

. . and found it can be simplified*beyond all recognition . . .*

Quote:

Since , we have:

. .

Differentiate:

. .

Multiply top and bottom by

. .

Therefore: .

If*that's*what they did, no wonder your answer is different!

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Let's see what they can do to #1 . . .

Then: .

Get a common denominator: .

- July 1st 2006, 11:24 PMc_323_hQuote:

Originally Posted by**Soroban**

- July 2nd 2006, 12:40 AMSoroban
Hello again, c_323_h!

Quote:

Does anyone know of any other ways to solve this one?

Since

. . we have: .

Quotient Rule: .

We have: .

Multiply top and bottom by

Therefore: .

- July 2nd 2006, 10:15 AMc_323_h
thanks. what does

*differentiate with respect to x*mean? - July 2nd 2006, 10:48 AMThePerfectHackerQuote:

Originally Posted by**c_323_h**

Basically, just differentiate the function.