Im stuck on this problem: 5cosx-x=0; they ask to use a graphing utility to approximate the answer.
Last edited by >_<SHY_GUY>_<; May 22nd 2008 at 07:13 PM. Reason: solved one of the problems
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You can approximate it by Newton's method. Graph it and see where it crosses the x-axis.
Originally Posted by >_<SHY_GUY>_< Im stuck on this problem: 5cosx-x=0; they ask to use a graphing utility to approximate the answer. Depending on your graphing utility the commands are different. Here is maple 11. You could also "guess" the x intercepts by looking at the graph I hope this helps.
Originally Posted by TheEmptySet Depending on your graphing utility the commands are different. Here is maple 11. You could also "guess" the x intercepts by looking at the graph I hope this helps. what if it is on the interval (0, 2pi]?
Originally Posted by >_<SHY_GUY>_< what if it is on the interval (0, 2pi]? The graph shows from $\displaystyle [-2\pi,2\pi]$ so just ignore the part of the graph to the left of the y axis. So the only root would be $\displaystyle x \approx 1.30644$
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