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Math Help - Differentiation Question

  1. #16
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Pikeman85 View Post
    Still not getting it. I'm very dense about a lot of the simpler bits. I've got most of the differentiation ones done, but this one eludes me
    f(2) from left equals 4+12+13=29

    f(2) from right 2a+b

    f'(2) from left equals 4+6=10

    f'(2) from right equals a

    so a=10

    and 2a+b=29

    so a=10 and b=9
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  2. #17
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    Wow, that was a lot easier than what I was trying to do. I knew it was something easy I had to do as well. The worst bit is that it's my algebra skills that have gone down over the years, over everything else.
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  3. #18
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Pikeman85 View Post
    Wow, that was a lot easier than what I was trying to do. I knew it was something easy I had to do as well. The worst bit is that it's my algebra skills that have gone down over the years, over everything else.
    Well dont fret! After a course in calc your alg. skills will be given a makeover...that or you fail
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  4. #19
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    Find the equation of the tangent line to the curve y = 2x cos x at the point (pi , -2\pi). The equation of this tangent line can be written in the form y = mx+b where




    m =



    b =




    Now I know I have to plug this into f(x-h) - f(x)/h

    or is there a different way to do it?
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  5. #20
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Pikeman85 View Post
    Find the equation of the tangent line to the curve y = 2x cos x at the point (pi , -2\pi). The equation of this tangent line can be written in the form y = mx+b where




    m =



    b =




    Now I know I have to plug this into f(x-h) - f(x)/h

    or is there a different way to do it?
    Yes, the equation of a tangent line is y-f(x_0)=f'(x_0)(x-x)0)

    where f'(x_0) is the derivative evaluated at the point
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  6. #21
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    ( f(3 x^{2}) ) = 9 x^{3}.

    How do I calculate f'(x) in this case?

    I swear this is the last question I ask tonight!
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