Originally Posted by Moo Hello would you mind explaining that again. I dont get how you get that? Thanks
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Following up on TheEmptySet's post. We have Since back substitute and This result is called as "telescoping sum."
Originally Posted by taurus would you mind explaining that again. I dont get how you get that? Thanks Do you agree that ? Now, let's find out A and B such that : So we want -> And So This may be better doing this way for you..
last question Moo on that new way you showed me how would i get the sum? i stick values for n of 0, 1, 2, 3... and see if there is number not reapeating?
Originally Posted by taurus last question Moo on that new way you showed me how would i get the sum? i stick values for n of 0, 1, 2, 3... and see if there is number not reapeating? The number which does not repeat is always the first one in a telescoping sum... I gave you a link to wikipedia and TheEmptySet explained it well. And n begins at 1
but for the new method seems more understandable i put n = 1 and got -1/30 which aint the sum:?
It's n=1 in
but you said (-1/n+4) + (1/n+5) why dont you add?
Because 1/(n+5) annulates with the following term, and so on... Just write the few first terms of the series on a paper, and you will see that..
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