Question

A curve is such that $\displaystyle \frac{dy}{dx} = \frac{4}{\sqrt(6 - 2x)}$, and $\displaystyle P(1,8)$ is a point on the curve. Find the equation of the curve.

Attempt:

$\displaystyle \frac{dy}{dx} = \frac{4}{\sqrt(6 - 2x)}$

$\displaystyle \int 4(6-2x)^{-\frac{1}{2}}dx$

I don't know how to integrate it.. need help!