Weird limits problem
I just got my test back today, and missed a few problems. Two of these problems were similar to this one:
With this problem, you're trying to find the value of 'a' where it will make the limit possible. The answers are: a=28. the limit: 1.6
I saw this and had no clue how to work it, didn't even see it in the homework (Thinking)
Could any explain?
We can see that the (x+3) factor is causing the problem if we directly evaluated the limit by plugging in x = -3. So, let's assume that the numerator is divisible by (x+3) so that
the (x+3)'s will cancel and all that remains is to plug in x = -3 directly.
So, we do long division and you should get the remainder:
Since we want (x+3) to factor in nicely, we can assume that the remainder is 0. i.e.
So we have:
You know where to go from there ;)
Or if you learned l'hopital's, you could go that route and set the numerator equal to 0 and solve for a. Then differentiate and solve the limit.
Hmm... you lost me around (Speechless)
Originally Posted by bobak
Ah, I see what you did there. Poor factoring on my part. Though, is long division necessary? (Surprised)
Originally Posted by o_O
Thank you both for responding! (Clapping)
Allow me to give you a simple solution.
You want to be a factor of .
Thus use the factor/root theorem and solve for a.
Thank you good sir! Makes sense now (Itwasntme)
Originally Posted by Plato