Hello I need help differentiating the following function using the Composite Rule, f(x) = e^(x(4-x)/6) Thanks
Last edited by flyingscotsman; May 20th 2008 at 01:38 PM. Reason: function didn't show power correctly
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Originally Posted by flyingscotsman Hello I need help differentiating the following function using the Composite Rule, f(x) = ex(4-x)/6 Thanks If this is $\displaystyle f(x)=e^{\frac{x(4-x)}{6}}$ then $\displaystyle f'(x)=e^{\frac{x(4-x)}{6}}\cdot\bigg(\frac{x(4-x)}{6}\bigg)'=e^{\frac{x(4-x)}{6}}\bigg(\frac{4-2x}{6}\bigg)$
Originally Posted by flyingscotsman Hello I need help differentiating the following function using the Composite Rule, f(x) = e^x(4-x)/6 Thanks $\displaystyle f(x) = \frac{e^x (4-x)}{6}$ $\displaystyle f'(x) = \frac{1}{6} \left( e^x (4-x) - e^x \right) $
Many thanks Mathstud28 for all your help.
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