y" -4y' + 3y = 0 y(0)= -1 ; y'(0)= 3 Here's how I tried to solve it: 1. r^2 - 4r + 3 = 0 2. (r-1)(r-3) = 0 3. r= 1, 3 4. Thus y=c1(e^x) + c2(e^3x) But now I'm stuck. How do I use the initial values to solve for c1, c2? Thanks, Jim
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Originally Posted by Jim Newt y" -4y' + 3y = 0 y(0)= -1 ; y'(0)= 3 Here's how I tried to solve it: 1. r^2 - 4r + 3 = 0 2. (r-1)(r-3) = 0 3. r= 1, 3 4. Thus y=c1(e^x) + c2(e^3x) But now I'm stuck. How do I use the initial values to solve for c1, c2? Thanks, Jim You now have a system of equations like so: I'm sure you can finish this!
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