1. ## Moving Particle Equation

Q: With the following two equations, find the value of $u$:
$2ut = 735 \ \ \ \ \ \ \ \ \ \ \ \ \dots (1)$
$0 = 3ut - 21 gt^2\ \ \ \ \dots (2)$.

The correct answer is $u=24.5$. I'm getting an incorrect answer. Can someone do this question and see if they obtain the correct answer so I can compare with mine. Thanks in advance.

2. Originally Posted by Air
Q: With the following two equations, find the value of $u$:
$2ut = 735 \ \ \ \ \ \ \ \ \ \ \ \ \dots (1)$
$0 = 3ut - 21 gt^2\ \ \ \ \dots (2)$. Mr F adds: => 0 = ut - 7gt^2.

The correct answer is $u=24.5$. I'm getting an incorrect answer. Can someone do this question and see if they obtain the correct answer so I can compare with mine. Thanks in advance.
Substitute ut from (1) into (2), take g = 9.8 and solve for t (keeping only the positive value): t = 2.31 seconds.

Substitute t into (1) and solve for u: u = 159.1 metres.

Then again, I'm terrible with arithmetic ....

3. Originally Posted by mr fantastic
Substitute ut from (1) into (2), take g = 9.8 and solve for t (keeping only the positive value): t = 2.31 seconds.

Substitute t into (1) and solve for u: u = 159.1 metres.

Then again, I'm terrible with arithmetic ....
But that contradicts the marks scheme answer as $u=24.5$.

4. Originally Posted by Air
But that contradicts the marks scheme answer as $u=24.5$.
Could you completely specify the problem (as in originally how it was stated)?
I think that will help

5. Originally Posted by Isomorphism
Could you completely specify the problem (as in originally how it was stated)?
I think that will help
Q:
A particle $P$ is projected with velocity $(2u \b{i} + 3u \b{j}) \ \text{ms}^{-1}$ for a point $O$ on a horizontal plane, where $\b{i}$ and $\b{j}$ are horizontal and vertical unit vectors respectively. The particle $P$ strikes the plane at a point $A$ which is $735m$ from $O$.

Show that $u=24.5$.

6. Originally Posted by Air
Q: With the following two equations, find the value of $u$:
$2ut = 735 \ \ \ \ \ \ \ \ \ \ \ \ \dots (1)$
$0 = 3ut - 21 gt^2\ \ \ \ \dots (2)$.

The correct answer is $u=24.5$. I'm getting an incorrect answer. Can someone do this question and see if they obtain the correct answer so I can compare with mine. Thanks in advance.
Well why did you write the second equation like that?

The correct equation is

$0 = 3ut - \frac12 gt^2$

And I solved it to get $u=24.49$