# Integration Confusion

• June 28th 2006, 04:03 PM
Dae
Integration Confusion
Problem solved.
• June 28th 2006, 04:20 PM
Jameson
I don't follow your work, but using the integrating method goes like this.

$\frac{dM}{dt}=-kM$

$\frac{1}{M}dM=-kdt$

$\ln|M|=-kt+C$

$M=Ce^{-kt}$
• June 28th 2006, 04:44 PM
Dae
Thanks Jameson, I think I get that.
• June 28th 2006, 06:07 PM
ThePerfectHacker