∫01 ∫y√y (2x2 + y) dy dx
$\displaystyle \int_{0}^{1}\int_{y}^{\sqrt{y}}(2x^2+y)\,dy\,dx$
Its not going to work out...could it be this?
$\displaystyle \int_{0}^{1}\int_{y}^{\sqrt{y}}(2x^2+y)\,dx\,dy$
$\displaystyle \implies \int_{0}^{1}\left.\left[\frac{2}{3}x^3+yx\right]\right|_{y}^{\sqrt{y}}\,dy$
$\displaystyle \implies \int_{0}^{1}\left[\frac{5}{3}y^{\frac{3}{2}}-\frac{2}{3}y^3-y^2\right]\,dy$
$\displaystyle \implies \left.\left[\frac{2}{3}y^{\frac{5}{2}}-\frac{1}{6}y^4-\frac{1}{3}y^3\right]\right|_{0}^{1}$
$\displaystyle \implies \frac{2}{3}-\frac{1}{6}-\frac{1}{3}=\color{red}\boxed{\frac{1}{6}}$.
Hope this helped you out!