# Inverse laplace transform

• May 18th 2008, 08:59 AM
boab
Inverse laplace transform
I've been aske dto inv lap trans the following:

s/(S^2 + 4s + 3)

I've gotten to

= s/((s+2)^2-1)

which I think is right but I'm not really sure where to go from here.

Anyone help?
• May 18th 2008, 09:03 AM
galactus
Try a partial fraction:

$\frac{3}{2(s+3)}-\frac{1}{2(s+1)}$

Then we get a ilaplace of:

$\frac{3}{2}e^{-3t}-\frac{1}{2}e^{-t}$
• May 18th 2008, 09:08 AM
boab
Thanks Galactacus. I've just realised I've been a right eejit. Thanks for pointing out the obvious!