
Assessment Help
so far, g'(t) = 95e^0.25t * [1+19e^0.25t]^2
where g'(t) is the growth rate formula
the thing i have to do is find the mean height of the tree's and how many years that i expect the process would occur.
mean = 2.821
Integrate g'(t) = 95e^0.25t * [1+19e^0.25t]^1
95e^0.25t = 380e^0.25t+C
[1+19e^0.25t]^1 = 4.75e^0.25t(1+19e^0.25t)^1 +c
4.75e(sigma :confused: ) [1+19e^0.25t]^1.dt = 20(1+19e^0.25t)^1+c
at this point you are to find c
let g=0 & t=0
0(0) = 20(1+19e^0.25t)^1+c
0(0) = 20(20)^1+c
0(0) = 1+c
therefore c=1
at this time you are to find the value of t when g=2.821
2.821(t [dont know if this has to be here]) = 20(1+19e^0.25t)^(2or1) 1 (dunno if its supposed to be 2or1)
3.821(t) = 20(1+19e^0.25t)^(2or1)
0.19105(t)=(1+19e^0.25t)^(2or1)
0.19105(t)= 1 / (1+19e^0.25t)^(2or1)
if ^2 = 1/(1+19e^0.25t)x(1+19e^0.25t)
if ^1 = 1/1+19e^0.25t
Either way im lost, please help!

evil trees 1
0.191=1/(1+19e^0.25t)
1+19e^0.25x=1/0.191
1+19e^.25x=5.24
19e^0.25x=4.24
e^0.25x=0.223
ln0.223=0.25x
1.5=0.25x
x=6
6years to rech 2.82 :)