Originally Posted by

**Sweeties** Hello everyone!

i was asked to use the quotient rule to differentiate

h(x) = ( 1 + ln(x) ) / x where x > 0

I got

k'(x) = ( x + (1/x) - 1 + ln(x) * 1 ) / x^2

k'(x) = ( ln(x) ) / x^2

which i think is right.

it then asks me to use the above answer to find the general soltion of the differentisl equation

dy/dx = -(( ln(x) ) / x^2)) y^1/2 where x>0 and y>0

and give the solution in implicit form which i can't do. i am also not sure how to integrate ln(x), i find it confusing.