## Is it a Holder continuous function??

Define a real function $h:[-1,1]\to R$ by:

$h(x)=\int_{-1}^x\frac{g(t)}{\sqrt{1-t^2}}dt$, where $h(-1)=h(1)=0$

$g\in C[-1,1]$, i.e., $g$ is continuous in [-1,1].

I would like to know if the function $h$ is Holder continuous in [-1,1].

Thanks.