Find the limit.

$\displaystyle

\mathop {\lim }\limits_{x \to 7^ - } e^{3/(7 - x)}

$

So I said, let

$\displaystyle

t = 7 - x

$

If $\displaystyle

x \to 7^ -

$ then $\displaystyle

t \to 0

$

.....does $\displaystyle

t \to 0

$ approach from the right of left?

Sorry, i'm a bit rusty on limits. I haven't seen them in a while! Thanks for the help.