Find y' simplifying where possible y = 2x^3 − 5x + 2e^x − 7lnx the last bit of this function is really throwing me out not really sure where to start
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Originally Posted by smplease Find y' simplifying where possible y = 2x^3 − 5x + 2e^x − 7lnx the last bit of this function is really throwing me out not really sure where to start $\displaystyle f(x)=2x^3-5x+2e^{x}-7\ln(x)$ $\displaystyle f'(x)=6x^2-5+2e^{x}-\frac{7}{x}$ This is because $\displaystyle \frac{D[e^{u(x)}]}{dx}=u'(x)\cdot{e^{u(x)}}$ and $\displaystyle \frac{D[\ln(u(x))]}{dx}=\frac{u'(x)}{u(x)}$
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