using a conjucate.. can someone show me how they would solve this? thanks. lim x-> infinite [2x - squareroot(4x^2+1)]
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Originally Posted by Legendsn3verdie using a conjucate.. can someone show me how they would solve this? thanks. lim x-> infinite 2x - squareroot(4x^2+1) Multiplying by the conjugate we get Using the fact that we get
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