What does the function f(x)=1-2^(-x) approach as x goes to infinity?
I was trying to be practical opossed to formal...I dont do things like that...but when showing how to do something instead of just saying $\displaystyle \lim_{x\to\infty}\frac{1}{2^{x}}=0$ I like to show WHY it is
...it is just my preference...but you are correct in that it is informal and not to be done on tests