Thread: differentiate the following: help!

$\displaystyle y=exp(x^{3}+lnx) $

Originally Posted by skystar

$\displaystyle y=exp(x^{3}+lnx) $

Do you mean:
$\displaystyle e^{x^3+lnx}$

If so:

$\displaystyle \frac{d}{dx}e^{x^3+lnx}=(e^{x^3+lnx})(3x^2+\frac{1 }{x})$

If I remember correctly.