$\displaystyle y=exp(x^{3}+lnx) $
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Originally Posted by skystar $\displaystyle y=exp(x^{3}+lnx) $ Do you mean: $\displaystyle e^{x^3+lnx}$ If so: $\displaystyle \frac{d}{dx}e^{x^3+lnx}=(e^{x^3+lnx})(3x^2+\frac{1 }{x})$ If I remember correctly.
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