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Math Help - simpson's rule

  1. #1
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    simpson's rule

    Hi, in the table below are cross-sectional areas for a strip of soil every 7.2m in lg.

    heres the table of the results

    Distance (m) X-section Area (m2)
    0.00 0.88
    1.20 1.56
    2.40 1.84
    3.60 2.39
    4.80 1.41
    6.00 0.37
    7.20 0.34

    i need to find the volume to be excavated using the prismoidal rule. havent got a clue how to do it!
    If someone could help me out as i have got to hand this assignment in later today!


    Thanks PPL

    Billy
    Last edited by billybob88; May 13th 2008 at 02:21 AM. Reason: table from excel didnt come out in the post
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by billybob88 View Post
    Hi, in the table below are cross-sectional areas for a strip of soil every 7.2m in lg.

    heres the table of the results

    Distance (m) X-section Area (m2)
    0.00 0.88
    1.20 1.56
    2.40 1.84
    3.60 2.39
    4.80 1.41
    6.00 0.37
    7.20 0.34

    i need to find the volume to be excavated using the prismoidal rule. havent got a clue how to do it!
    If someone could help me out as i have got to hand this assignment in later today!


    Thanks PPL

    Billy
    This is the same as Simpson's rule.

    V \approx \frac{h}{3}[A_1+4A_2+2A_3+4A_4+2A_5+4A_7+A_7]

    RonL
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by billybob88 View Post
    Hi, in the table below are cross-sectional areas for a strip of soil every 7.2m in lg.

    heres the table of the results

    Distance (m) X-section Area (m2)
    0.00 0.88
    1.20 1.56
    2.40 1.84
    3.60 2.39
    4.80 1.41
    6.00 0.37
    7.20 0.34

    i need to find the volume to be excavated using the prismoidal rule. havent got a clue how to do it!
    If someone could help me out as i have got to hand this assignment in later today!


    Thanks PPL

    Billy
    Quote Originally Posted by CaptainBlack View Post
    This is the same as Simpson's rule.

    V \approx \frac{h}{3}[A_1+4A_2+2A_3+4A_4+2A_5+4A_7+A_7]

    RonL
    So in this case h=120, and so:

    V \approx 40[0.88+4\times 1.56+2\times 1.84+4\times 2.39+2\times 1.41+4\times 0.37+0.34]

    RonL
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